Question

This is my foreach function

<? foreach($Selected as $row)
     $value = $row['dPath'];
     $imgp =  base_url()."images"."/".$value;
{?>


<td>
  <?=$row['dFrindName'].'</br>';?>
  <?php */?> <img src="<?=$imgp ?>" name="b1" width="90" height="80" border="0"/>
</td>
<? }}?>
Print_r($Selected);
results in `Array ( [0] => Array ( [dFrindName] => chandruCP 
                    [dPath] => m11on.gif ) [1] => Array ( [dFrindName] => udaya 
                    [dPath] => logo.jpg ) )`

but only my last value of the array is displayed on image
I can get the name udaya and logo.jpg on the screen
But i cant get chandruCP and m11on.gif
why it is so how can i get all the values and image on scrren

Answer 1

There are a few things wrong with your code:

1. The opening bracket { of your foreach is in the wrong place.
2. You have a random closing comment in the middle of your code
3. You are using invalid HTML, the correct way to write a self-closing is <br />

Here is your code rewritten to correct these errors, it should produce what you are trying to achieve:

<?
foreach ($Selected as $row) {
  $imgp =  base_url()."images"."/".$row['dPath'];
?>
  <td>
    <?=$row['dFrindName'];?><br />
    <img src="<?=$imgp;?>" name="b1" width="90" height="80" border="0" />
  </td>
<? } ?>