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Home/ Questions/Q 5950493
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T17:24:04+00:00 2026-05-22T17:24:04+00:00

This is my function, when I call my_conv(2312144, 10, 10), it gives me bad

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This is my function, when I call my_conv(“2312144”, 10, 10), it gives me “bad argument” error

my_conv(S, Start, End) ->
  Res = <<Start:8, End:8, S:1024>>.
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  1. Editorial Team
    Editorial Team
    2026-05-22T17:24:05+00:00Added an answer on May 22, 2026 at 5:24 pm

    A string cannot be used inside a binary expression without conversion. You need to convert the string to a binary by using list_to_binary(S).

    I would recommend the following expression:

    my_conv(S, Start, End) ->
        list_to_binary(<<Start:8, End:8>>, S]).
    

    (Note here that list_to_binary/1 actually accepts a deep IO list and not just a pure string).

    If you intend to pad your binary to 1024 bytes (or 1040 including your newlines) you can do so afterwards:

    my_conv(S, Start, End) ->
        pad(1040, list_to_binary(<<Start:8, End:8>>, S])).
    
    pad(Width, Binary) ->
        case Width = byte_size(Binary) of
            N when N =< 0 -> Binary;
            N -> <<Binary/binary, 0:(N*8)>>
        end.
    
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