Question

This is my grid:

   colModel: [  

            { name: "userGroupID", index: "userGroupID", width: 50, hidden:true, align: "left" }, 
            //{ name: "userId", index: "userId", width: 75, align: "left",title:false,search:false, sorttype:'text'},
            { name: "userInfoID", index: "userInfoID", width: 75, align: "left",hidden:true,title:false,search:true, sorttype:'text'},
            { name: "userID", index: "userID", width: 75, align: "left",title:false,search:true, sorttype:'text'},
            { name: "firstName", index: "firstName", width: 75, align: "left",title:false,search:false, sorttype:'text'},
            { name: "organizationName", index: "organizationName", width: 75, align: "left",title:false,search:false, sorttype:'text'},
            { name: 'action', index: 'action', width: 70, align: "left",sortable: false, search:false}          
            ],

I am getting data from server to populate grid and trying to add my own data to the grid.
I used

var grid = jQuery("#jqTable");
   var data = [{"userGroupID":"2","userInfoID":"2","userID":"userID","firstName":"firstName","organizationName":"organizationName"}];
        //jQuery("#jqTableList").addRowData("userGroupID",data);
        grid.jqGrid('addRowData','1',data);
        //jQuery("#jqTableList").trigger("reloadGrid");

It is saying: TypeError: t.p is undefined

u = t.p.rownumbers === true ? 1 : 0;

Please help me..

Answer 1

You use addRowData method in the wrong way. If you want to use it to add multiple rows you should change the first parameter of addRowData method.

You can read the following in the documentation of jqGrid:

This method can insert multiple rows at once. In this case the data
parameter should be array defined as [{name1:value1,name2: value2…},
{name1:value1,name2: value2…} ] and the first option rowid should
contain the name from data object which should act as id of the row.
It is not necessary that the name of the rowid in this case should be
a part from colMode

So if for example userGroupID contains the unique values which could be interpreted as id of every row you can use addRowData in the following form

grid.jqGrid('addRowData', 'userGroupID', data);

In your current your code which you posted the column with the name '1' will be interpreted as id. By the way it’s very important to specify the id values for the grid. If the column userGroupID (or some other column of the grid) really could be used as id you should add key: true property in the column. The property can used only for one column.

In general I don’t recommend to use addRowData for filling the grid if the data are known at the time of creating of the grid (see the answer for details). If you have grid with datetype: "local" it’s much more effective to use data: yourArrayWithData. If you need to replace data of the grid you can use

grid.jqGrid("getGridParam").data = myNewData;

See the answer