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Home/ Questions/Q 365515
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:32:40+00:00 2026-05-12T13:32:40+00:00

This is my Hello World Remoting App. using System; using System.Collections.Generic; using System.Text; namespace

  • 0

This is my Hello World Remoting App.

using System;
using System.Collections.Generic;
using System.Text;

namespace Remoting__HelloWorld.UI.Client
{
    public interface MyInterface
    {
        int FunctionOne(string str);
    }
}

using System;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Tcp;

namespace Remoting__HelloWorld.UI.Client
{
    class MyClient
    {
        public static void Main()
        {
            TcpChannel tcpChannel = new TcpChannel();

            ChannelServices.RegisterChannel(tcpChannel);

            MyInterface remoteObj = (MyInterface) 
            Activator.GetObject(typeof(MyInterface), "tcp://localhost:8080/FirstRemote");

            Console.WriteLine(remoteObj.FunctionOne("Hello World!"));
        }
    }
}


using System;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using Remoting__HelloWorld.UI.Client;

namespace Remoting__HelloWorld.UI.Server
{
    public class MyRemoteClass : MarshalByRefObject, MyInterface
    {
        public int FunctionOne(string str)
        {
            return str.Length;
        }
    }
}


using System;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Tcp;

namespace Remoting__HelloWorld.UI.Server
{
    class Program
    {
        static void Main(string[] args)
        {
            TcpChannel tcpChannel = new TcpChannel(9999);

            ChannelServices.RegisterChannel(tcpChannel);

            RemotingConfiguration.RegisterWellKnownServiceType(typeof(MyRemoteClass), "FirstRemote", WellKnownObjectMode.SingleCall);

            System.Console.WriteLine("Press ENTER to quit");
            System.Console.ReadLine();
        }
    }
}

But after running this app, I am getting the following Exception:

No connection could be made because the target machine 
actively refused it 127.0.0.1:8080

How can I fix this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:32:41+00:00Added an answer on May 12, 2026 at 1:32 pm

    Either change the server like this:

    TcpChannel tcpChannel = new TcpChannel(8080);
    

    or change the client like this:

    Activator.GetObject(typeof(MyInterface), "tcp://localhost:9999/FirstRemote");
    

    On the server side, you’re opening a channel on the specified port number (in your example, you’re using port 9999). In essence, this tells the server to ‘listen’ for incoming requests on port 9999. On the client side, you tell it what port number to connect to (in your example, you’re using port 8080). So you have a situation where your server is listening on port 9999, but your client is trying to connect on port 8080. These port numbers must match.

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