Question

This is my method for converting a String Hex to a decimal:

private int fromHexToPercent(String hex){
    int decimal = Integer.parseInt(hex, 16);
    return decimal;
}

When i call it on these values: #ffe87e, #ffc6bb, #528b7a, #9b81ff, #7d6a32, #000c40 among others I get the following exception on this line:

   int decimal = Integer.parseInt(hex, 16);

Error:

at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:481)

Here is my method for converting from rgb to hex, i got a feeling that Java has å problem with this line: hex = “0” + hex;. But it needs to be there to get the hex-code right.

    public static String toHex(int r, int g, int b) {
return "#" + toBrowserHexValue(r) + toBrowserHexValue(g) +  toBrowserHexValue(b);
}

private static String toHexValue(int number) {
    String hex = Integer.toHexString(number & 0xff);
    while (hex.length() < 2) {
        hex = "0" + hex;
    }
    return hex;
}

Really hope somebody can see a solution to this problem =)

Answer 1

The only valid hex digits are 0-9 and a-f (or A-F). # is not a valid hex digit.