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Home/ Questions/Q 9291711
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T20:42:47+00:00 2026-06-18T20:42:47+00:00

This is my model : public class Stages { public int Id { get;

  • 0

This is my model :

 public class Stages
  {
      public int Id { get; set; }
      public string Code { get; set; }
      public string Name { get; set; }
      public string Des { get; set; }
      public string View_Count { get; set; }
  }

My Controller :

 public ActionResult ViewStages()
    {
        return View();
    }

And my view :

<%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" 

Inherits="System.Web.Mvc.ViewPage<IEnumerable<Project.Models.Stages>>" %>

//Some Code...

<% foreach (var item in Model)
       { %>
    <tr>
        <td>
            <%: Html.DisplayFor(modelItem => item.Code)%>
        </td>
        <td>
            <%: Html.DisplayFor(modelItem => item.Name)%>
        </td>
        <td>
            <%: Html.DisplayFor(modelItem => item.Des)%>
        </td>
        <td>
            <%: Html.DisplayFor(modelItem => item.View_Count)%>
        </td>
        <td>
            <%: Html.ActionLink("Edit", "Edit", new { id = item.Id })%> |
            <%: Html.ActionLink("Details", "Details", new { id = item.Id })%> |
            <%: Html.ActionLink("Delete", "Delete", new { id = item.Id })%>
        </td>
    </tr>
<% }%>

</table>

</asp:Content>

And I always get this error : Object reference not set to an instance of an object.
and the error occurred when it reaches the foreach loop. What is the problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T20:42:48+00:00Added an answer on June 18, 2026 at 8:42 pm

    Because you didn’t initialize it

       public ActionResult ViewStages()
       {
            //this initialize your model
            var viewModel=new List<Stages>()       
                              {
                                  new Stages()
                                      {
                                          Id = 1,
                                          Code = "any code",
                                          //etc
                                      }
                              }; 
            return View(viewModel);   //you have to pass the model to the view
         }
    
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