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Home/ Questions/Q 700221
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:28:24+00:00 2026-05-14T03:28:24+00:00

This is my php code (I already have a connection to the db): $result

  • 0

This is my php code (I already have a connection to the db):

$result = mysql_query("SHOW TABLE STATUS FROM mydb LIKE 'mytable';");
     while ($array = mysql_fetch_array($result)) {
          $updatetime = $array['Update_time'];
     }

echo $updatetime;

I get:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource.

I am running MySQL 5.0.89 and PHP5.

I do not want to add a new field to the table… I want to use the table status…

Any help?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:28:24+00:00Added an answer on May 14, 2026 at 3:28 am

    Figured it out. Not sure if this is the perfect way, but it works…

    $result = mysql_query("SHOW TABLE STATUS FROM mydb LIKE 'mytable';");
    foreach ($result as $data) {
        $updatetime = $data->Update_time;
    }
    
    echo $updatetime;
    

    You can then parse the raw timestamp with substr.

    P.S. As I was doing this for WordPress, I am including the code specifically for working in the WordPress DB…

    global $wpdb;
    define('FOO_TABLE', $table_prefix."footable");
    
    $result = $wpdb->get_results("SHOW TABLE STATUS LIKE '".FOO_TABLE."';");
    foreach ($result as $data) {
      $updatetime = $data->Update_time;
    }
    
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