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Home/ Questions/Q 7163955
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:59:20+00:00 2026-05-28T13:59:20+00:00

This is my query using entity manager. Trying to join 2 table with play

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This is my query using entity manager. Trying to join 2 table with play framework and jpa.

 List<Object> joinQryResult = JPA.em().createNativeQuery(
         "select e.elementname as elementname, " +
         "c.comparetype as comparetype, " + 
         "jd.matchvalue as matchvalue " +
         "from details jd " +
         "join elements e on jd.elementnamerid = e.rid " +
         "join comparers c on jd.comparetyperid = c.rid " +
         "where jd.rid = " + temp.rid).getResultList();

 Not sure how to iterate and get the values from List<Object>

I tried this

List<MyClass> myClass = (List<MyClass>)(Object)joinQryResult;


for(MyClass myC:jd)
{
 System.out.println(myC.ElementName); //intellisense shows the property here
}

MyClass definition: ttrying to convert List to this type

public class MyClass {

    public String ElementName;

    public String CompareType;

    public String MatchValue;

    public JobDetails(String ElementName, String CompareType, String MatchValue)
    {
        this.ElementName = ElementName;

        this.CompareType = CompareType;

        this.MatchValue = MatchValue;
    }
}

Get this error

ClassCastException occured : [Ljava.lang.Object; cannot be cast to models.MyClass
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:59:21+00:00Added an answer on May 28, 2026 at 1:59 pm

    The result of the query will be a List with the elements of the objects being the corresponding object type.

    You could do as follow to map to your object

        List<Object[]> results = query.getResultList();
        JobDetails jobDetail = null;
        for (Object[] objects : results) {
            jobDetail = new JobDetail((String) objects[0],(String) objects[1],(String) objects[2])
        }
    
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