Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8660687
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T16:19:02+00:00 2026-06-12T16:19:02+00:00

This is my scenario in Java: interface I{} class A implements I{} class B

  • 0

This is my scenario in Java:

interface I{}
class A implements I{}
class B extends A{}

So, now which class needs to implement the interface’s I methods? What if A and B classes share implementation?
Best regards

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T16:19:03+00:00Added an answer on June 12, 2026 at 4:19 pm

    class A has to provide all implementations since it’s not abstract. See here for more details.

    class B can override any/all of those methods.

    If you make A abstract (as a class), then it can provide abstract methods for those methods in the interface (essentially just declaring them as abstract) and B would provide the only implementation.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This scenario comes up often, now that I use LinkToSql and the classes it
i need to implement this scenario Brief about that is have two java based
I'm a little bit confused by this scenario: I have a class that implements
Consider this scenario for a Java application with Spring: public interface FooDao { @Transactional
In Java you can wait on every object, so this kind of scenario is
java.util.concurrent.ConcurrentLinkedQueue comes to mind, but is it really optimum for this two-thread scenario? I
Is this scenario even possible? class Base { int someBaseMemer; }; template<class T> class
In this scenario, I have 2 or more models: class Store(models.Model): name = models.CharField(max_length
Java generates a proxy class for a given interface and provides the instance of
Scenario 1 The skip listener interface is as below: public interface SkipListener<T,S> extends StepListener

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.