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Home/ Questions/Q 6982599
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:18:33+00:00 2026-05-27T18:18:33+00:00

This is my setting: display_startup_errors = on display_errors = On error_reporting = E_ALL |

  • 0

This is my setting:
display_startup_errors = on
display_errors = On
error_reporting = E_ALL | E_STRICT

//code1:
$a = "abcd";
xdebug_debug_zval('a');

The above line of code would create a zval container and associate it with the symbol a’. And would give the following o/p.

a: (refcount=1, is_ref=0)='abcd' 

consider the folowing code now:

//code2:
$a;
echo":";xdebug_debug_zval('a'); echo "<br/>";
$a = "abcd";
xdebug_debug_zval('a'); echo "<br/>";

would generate the o/p;

:
a: (refcount=1, is_ref=0)='abcd' 

from PHP manual’s Reference Counting Basics : A zval container is created when a new variable is created with a constant value

Does this mean that,

1] No symbol is created when code similar to line 1 of code2 i.e. $a; is encountered. Since     xdebug_debug_zval does not find the symbol / variable name ‘a’. As per the statement from     Reference Counting Basics no zval container is created.
2] A symbol is created only when code similar to line 3 of code2 i.e. $a = "abcd"; is encountered.     i.e. a symbol gets created only when the variable is associated with a constant value & as per the     statement from Reference Counting Basics a zval container is created and is associated with the     symbol ‘a’. And that line 1 of code2 i.e. $a; is a useless piece of code.

For info on xdebug_debug_zval visit here.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:18:34+00:00Added an answer on May 27, 2026 at 6:18 pm

    $b;
    xdebug_debug_zval('b'); echo "<br/> ";
    echo $b;
    

    The above code would output:

    Notice: Undefined variable: b in /path/to/file/file.php on line ‘some line number’

    The xdebug_debug_zval is not throwing any error in the above code though!!

    Assigining $b a constant value,

    $b = "hello";
    xdebug_debug_zval('b'); echo "<br/> ";
    echo $b;
    

    b: (refcount=1, is_ref=0)=’hello’
    hello

    The above code proves that a ‘symbol’/’variable name’ gets created only when a constant is associated with it
    i.e.
    A ‘symbol’/’variable name’ gets created only when there is a possibility of a zval getting created.

    A symbol can be created if a variable is assigned NULL.

    $b = null;
    xdebug_debug_zval('b'); echo "<br/> ";
    echo $b;
    

    The above code will output:

    b: (refcount=1, is_ref=0)=NULL

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