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Home/ Questions/Q 7787303
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T20:37:16+00:00 2026-06-01T20:37:16+00:00

This is my simple array: typeset -A foo foo[first]=first Value foo[second]=second Value And I

  • 0

This is my simple array:

typeset -A foo

foo["first"]="first Value"
foo["second"]="second Value"

And I want to do a function that would pick this array, do something and return it back to the script. e.g.

function changeThat {
    eval tmp=\$$1
    tmp["$2"]=$3
    return $tmp
}

I a way could go along in the script and do something like:

foo=changeThat foo "first" "a new first value"

And get a pretty result like

echo ${foo["first"]}
a new first value

Now this doesn’t work… Well, I’m aware the syntax is prob not quite right. But I got really lost going through the nuances of evals and scape echo (not to say that I hate it from the bottom of my soul). Besides, my reference is for bash and wouldn’t be the first time I miss some trick when it comes to ksh – For instance, I’ve been so far in ksh88, which does’t even have associative arrays, while most people say it should. Turns out that my AIX box does not agree. -_-

thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-01T20:37:18+00:00Added an answer on June 1, 2026 at 8:37 pm

    You can define your function like this:

    function changeThat {
      typeset -n ref="$1"
      typeset key="$2"
      typeset value="$3"
    
      ref["$key"]="$value"
    }
    

    typeset -n ref defines the ref variable as a reference to the variable specified by it’s value.

    When you make this call to the function:

    changeThat foo this "mow the lawn"
    

    The variable ref in function changeThat references the variable foo. Using ref is now just like using foo. After calling changeThat

        print ${foo["this"]}
    

    will now output “mow the lawn”.

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