This is my Table: and I am running this query, SELECT fruits,COUNT(*) as count

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Editorial Team

Asked: June 17, 20262026-06-17T07:27:48+00:00 2026-06-17T07:27:48+00:00

This is my Table:

This is my table

and I am running this query,

SELECT fruits,COUNT(*) as count FROM meva where owner = 'bill' GROUP BY fruits ORDER BY count

and i am getting result as

enter image description here

Is it possible to get the other fruits items as 0 if not matched with owner like this,

Fruit   | count
Apple   ,   2
Mango   ,   0
Banana  ,   0
Strawberry ,0
Appricot,   0
Alfonso ,   0

A little modification in my query is most appreciated.
thanks

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Editorial Team · Answer 1 · 2026-06-17T07:27:50+00:00

Editorial Team

use SUM() and CASE

SELECT  fruits, 
        SUM(CASE WHEN owner = 'bill' THEN 1 ELSE 0 END) as `count `
FROM     meva 
GROUP BY fruits 
ORDER BY fruits

or by using IF (in MySQL only)

SELECT  fruits, 
        SUM(IF(owner = 'bill',1,0)) as `count `
FROM     meva 
GROUP BY fruits 
ORDER BY fruits

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