Question

This is my url:

from views import *

urlpatterns = patterns('',

    url(r'^$', BillingView.as_view(), name="index"),

)

and this is the method in my views.py:

class BillingView(BaseCompositeView):

    """
    A view that lets you record new billing information. This view includes all
    of the forms needed by the users on one page.
    """
    # We cannot easily override FormView since this view uses multiple forms

    template_name = "billing/base_billing.html"

etc.

Why is my view is not accessible?

Answer 1

Are you using django 1.4? What is the name of the project?

You probably want this for your import:

from project.billing.views import *

NameError means you’re referencing something that hasn’t been defined or declared in the current scope.

Edit:

To help diagnose the issue, try this:

python manage.py shell
>>> import django
>>> django.get_version()
'1.2.3'
>>> import sys
>>> sys.path
['/list/of/paths', '/and/other/paths/']

And just examine if the correct libraries are on your path. You might find that you’ve got a newer version of django in your site-libs folder amongst other things.

When are you getting the NameError? When running from the development server, or a production web server? Please show us the full error and stack trace.