This is my xml input
<issues>
<issue status="open" type="Bug">
<fix_versions>
<fix_version>6.14.0</fix_version>
<fix_version>6.13.0</fix_version>
<fix_version>6.12.0</fix_version>
</fix_versions>
<title>issue1</title>
<description>Description</description>
</issue>
<issue status="open" type="Feature">
<fix_versions>
<fix_version>6.13.0</fix_version>
</fix_versions>
<title>issue2</title>
<description>Description</description>
</issue>
<issue status="open" type="Improvement">
<fix_versions>
<fix_version>6.14.0</fix_version>
</fix_versions>
<title>issue3</title>
<description>Description</description>
</issue>
</issues>
And this is my xsl code
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="versions" match="issue" use="fix_versions"/>
<xsl:key name="type" match="issue" use="concat(fix_versions, '+', @type)"/>
<xsl:template match="issues">
<xsl:for-each select="//issue[generate-id(.)=generate-id(key('versions', fix_versions)[1])]">
<xsl:sort select="fix_versions" order="descending"/>
<xsl:variable name="version"><xsl:value-of select="fix_versions"/></xsl:variable>
<xsl:if test="//release[@version = \$version]">
<div class="release">
<a href="" class="version"><xsl:value-of select="\$version"/></a>
<div class="version" style="display:none;">
<xsl:for-each select="key('versions', fix_versions)[generate-id() = generate-id(key('type', concat(fix_versions, '+', @type))[1])]">
<div class="types">
<a href="" class="type"><xsl:value-of select="@type"/>s</a>
<div class="type" style="display:none">
<xsl:for-each select="key('type', concat(fix_versions, '+', @type))">
<div style="border-bottom:1px solid grey;">
<a href="" class="title"><xsl:value-of select="title"/></a>
<div class="toggle" style="display:none;">
<xsl:value-of select="description"/>
</div>
</div>
</xsl:for-each>
</div>
</div>
</xsl:for-each>
</div>
</div>
</xsl:if>
</xsl:for-each>
</xsl:template>
And this is what i get
<div class="version">
<a>6.14.0</a>
<div class="issues">
<div class="Bugs">
<a href="issue1">issue1</a>
<a href="issue7">issue7</a>
<a href="issue2">issue12</a>
<a href="issue17">issue17</a>
</div>
<div class="Improvements">
<a href="issue3">issue3</a>
<a href="issue9">issue9</a>
</div>
</div>
</div>
<div class="version">
<a>6.13.0</a>
<div class="issues">
<div class="Bug">
<a href="issue1">issue1</a>
<a href="issue11">issue11</a>
</div>
<div class="Feature">
<a href="issue2">issue2</a>
</div>
</div>
</div>
<div class="version">
<a>6.12.0</a>
<div class="issues">
<div class="Bug">
<a href="issue1">issue1</a>
</div>
</div>
</div>
All fine – The only Problem is that i only generate a key for fix_versions but i have the structure fix_versions/fix_version. So if there would be a node like <fix_versions>, he would create the key
<fix_version>6.14.0</fix_version>
<fix_version>6.13.0</fix_version>
<fix_version>6.12.0</fix_version>
</fix_versions>6.14.06.13.06.12.0 and would create a container for this version – but what i want is to put this issue into the three containers 6.14.0, 6.13.0 and 6.12.0. Is it genrally possible to duplicate one issue?
I tried something like <xsl:key name="versions" match="issue" use="fix_versions"/> and then use <xsl:for-each select="//issue[generate-id(.)=generate-id(key('versions', fix_versions)[1])]">, but he just creates the big group instead of sorting this issue into all of them.
Any idea?
Based on my guess of what the wanted result is:
When this transformation is applied on the provided XML document:
The presumed-wanted, correct result is produced: