Question

This is my XML

<root>
   <entry id="1">
      <value name="ID">11</value>
      <value name="ENABLE">0</value>
      <value name="NAME">USER1</value>
   </entry>
   <entry id="2">
      <value name="ID">11</value>
      <value name="ENABLE">0</value>
      <value name="NAME">USER2</value>
   </entry>
   <entry id="3">
      <value name="ID">12</value>
      <value name="ENABLE">0</value>
      <value name="NAME">USER1</value>
   </entry>
</root>

I need an XPath query to retrieve all the names whose id is 11.

I tried:

String xpath = "/root/entry/value[@name=ID/text()='11']/value[@name='NAME']";
String xpath = "/root/entry/value[@name=ID/text()='11']/NAME";

Can someone tell me what is wrong in my query?

EDIT:

Expected Output:

USER1
USER2

both these have ID = 11

Answer 1

This would be the correct path:

/root/entry[value[@name = 'ID'] = 11]/value[@name = 'NAME']

To retrieve a list of nodes, you need to use the version of xPath.evaluate() that takes a returnType parameter:

InputSource document = new InputSource(new FileInputStream("user1.xml"));
String xpath = "/root/entry[value[@name = 'ID'] = 11]/value[@name = 'NAME']";
NodeSet result = (NodeSet)xPath.evaluate(xpath, document, XPathConstants.NODESET); 
for(int index = 0; index < result.getLength(); index ++) {      
    Node node = result.item(index);
    String name = node.getNodeValue();
}