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Home/ Questions/Q 8030865
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T00:54:19+00:00 2026-06-05T00:54:19+00:00

This is no doubt simple, but my lack of knowledge about jquery makes it

  • 0

This is no doubt simple, but my lack of knowledge about jquery makes it complex for me. Basically I have this code:

$(document).ready( 
    function() {
    $( "#remove")
    .click(function() {
        alert("I have been clicked!");
        $(this).parent().parent().remove();
    }); 
});

I add a button to a table meant to remove it’s row (see above code). The button is as follows:

<td ><button id='remove' type='button'>Remove</button></td>

However, it does nothing when clicked. I think this may have something to do with the fact the button is created after the document is loaded… no idea what to do about it, though.

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  1. Editorial Team
    Editorial Team
    2026-06-05T00:54:23+00:00Added an answer on June 5, 2026 at 12:54 am
    $( "td").on('click', '#remove', function() {
            alert("I have been clicked!");
            $(this).parent().parent().remove();
        }); 
    

    As you’re trying to add button dynamically so you need delegate event handler (aka, live event).

    An in jQuery > 1.7 delegate event declare as

    $(container).on(eventName, target, handlerFunction);
    

    For more detail see .on()

    You have another option called .delegate() and its declaration process is:

    $(container).delegate(target, eventName, handlerFunction);
    

    So for your case it will look like:

    $('td').delegate('#remove', 'click', function() {
          alert("I have been clicked!");
          $(this).parent().parent().remove();
    });
    

    Note

    here container means the holder of #remove button which belong to DOM at page load. From you post it seem td, you may have something else (any valid jQuery selectors)

    If you can’t detect you container for #remove then use $(document) or $('body') instead of $('td').

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