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Home/ Questions/Q 1086655
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Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T22:50:25+00:00 2026-05-16T22:50:25+00:00

This is OK def variables=[ [‘var1′:’test1’], [‘var2′:’test2’], [‘var3′:’test3’] ] println ${variables.size()} variables.each{entry -> println

  • 0

This is OK

def variables=[
              ['var1':'test1'],
              ['var2':'test2'],
              ['var3':'test3']
              ]

println "${variables.size()}" 
variables.each{entry ->   
  println "${entry} "   
}

I got:

3
[var1:test1] 
[var2:test2] 
[var3:test3] 

but this caused problems

def variables=[
                  ['var1':'test1'],
                  ['var2':'test2'],
                  ['var3':'test3']
                  ]

    println "${variables.size()}" 
    variables.each{entry ->   
      println "${entry.key} "   
    }

since I got:

3
null 
null 
null 

I’m expecting:

3
var1
var2
var3 

what’s wrong with my code?

thank you!!!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:50:26+00:00Added an answer on May 16, 2026 at 10:50 pm

    You want:

    def variables=[
        'var1':'test1',
        'var2':'test2',
        'var3':'test3'
    ]
    
    println variables.size()
    variables.each{entry ->   
        println entry.key
    }
    

    Before you had an ArrayList containing three LinkedHashMap objects. The above code is a single LinkedHashMap with three entries. You also don’t need string interpolation, so I removed it.

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