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Asked: May 10, 20262026-05-10T15:02:56+00:00 2026-05-10T15:02:56+00:00

This is one of the possible ways I come out: struct RetrieveKey { template

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This is one of the possible ways I come out:

struct RetrieveKey {     template <typename T>     typename T::first_type operator()(T keyValuePair) const     {         return keyValuePair.first;     } };  map<int, int> m; vector<int> keys;  // Retrieve all keys transform(m.begin(), m.end(), back_inserter(keys), RetrieveKey());  // Dump all keys copy(keys.begin(), keys.end(), ostream_iterator<int>(cout, "\n")); 

Of course, we can also retrieve all values from the map by defining another functor RetrieveValues.

Is there any other way to achieve this easily? (I’m always wondering why std::map does not include a member function for us to do so.)

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  1. 2026-05-10T15:02:57+00:00Added an answer on May 10, 2026 at 3:02 pm

    While your solution should work, it can be difficult to read depending on the skill level of your fellow programmers. Additionally, it moves functionality away from the call site. Which can make maintenance a little more difficult.

    I’m not sure if your goal is to get the keys into a vector or print them to cout so I’m doing both. You may try something like this:

    std::map<int, int> m; std::vector<int> key, value; for(std::map<int,int>::iterator it = m.begin(); it != m.end(); ++it) {   key.push_back(it->first);   value.push_back(it->second);   std::cout << "Key: " << it->first << std::endl;   std::cout << "Value: " << it->second << std::endl; } 

    Or even simpler, if you are using the Boost library:

    map<int,int> m; pair<int,int> me; // what a map<int, int> is made of vector<int> v; BOOST_FOREACH(me, m) {   v.push_back(me.first);   cout << me.first << "\n"; } 

    Personally, I like the BOOST_FOREACH version because there is less typing and it is very explicit about what it is doing.

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