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Home/ Questions/Q 6198485
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T04:00:40+00:00 2026-05-24T04:00:40+00:00

this is part of an XML file I retrieve using AS3 E4X: <links> <link>

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this is part of an XML file I retrieve using AS3 E4X:

<links>
    <link>
      <label>Versions</label>
      <href>http://mylink1</href>
    </link>
    <link>
      <label>Configurations</label>
      <href>http://myLink2</href>
    </link>
</links>

I want to retrieve the values of labels, so I write:

document.links.link.label.text();

This returns VersionsConfigurations. I need this as Array ([Versions, Configurations]) but I would like not to use a loop. Is there any other way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T04:00:41+00:00Added an answer on May 24, 2026 at 4:00 am

    Well, this is a “don’t try this at home” solution, but here you are. 🙂

    You can use E4X search expression to do whatever you want to nodes of an XMLList.

    This works as follows: someXMLList.(expression), where expression is any AS3 code that can access each node’s properties and methods with no need of qualifying their names. For instance, you could do the following:

    yourXML.descendants("label").(trace("label text: ", text()));
    

    Note that I’m using text() here with no access . operations. Actually this will return an new XMLList for all nodes, where expression evaluated to true. Since trace() returns void, the resulting list will be empty. Internally there is of course a loop through all nodes of XMLLIst that is created by calling descendants() (or using .. operator).

    You can construct your array the same way.

    var doc:XML = 
    <links>
        <link>
          <label>Versions</label>
          <href>http://mylink1</href>
        </link>
        <link>
          <label>Configurations</label>
          <href>http://myLink2</href>
        </link>
        <link>
          <label>A label
    with
    multiple
    line 
    breaks</label>
          <href>http://myLink3</href>
        </link>
    </links>;
    
    trace(doc.descendants("label").text().toXMLString().split("\n"));
    /* Trace output (incorrect):
    Versions,Configurations,A label
    ,with
    ,multiple
    ,line 
    ,breaks
    */
    
    var list:Array = [];
    doc.descendants("label").(list.push(text().toString()));
    trace(list);
    /* Trace output (correct):
    Versions,Configurations,A label
    
    with
    
    multiple
    
    line 
    
    breaks
    */
    

    That may be useful when performing some complicated searches on an XMLList. However in your case I think you should instead use simple splitting of a string representation or a regular expression as Shane suggests.

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