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Editorial Team
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Asked: 2026-05-17T18:53:28+00:00

This is php script that fetches a table values from mysql (one row). &

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This is php script that fetches a table values from mysql (one row). & echoes it as JSON

<?php  
      $username = "user";  
      $password = "********";  
      $hostname = "localhost";  
      $dbh = mysql_connect($hostname, $username, $password) or die("Unable to 
      connect to MySQL");  
      $selected = mysql_select_db("spec",$dbh) or die("Could not select first_test");  
      $query = "SELECT * FROM user_spec";  
      $result=mysql_query($query);     
      $outArray = array(); 
      if ($result) { 
      while ($row = mysql_fetch_assoc($result)) $outArray[] = $row; 
       } 
      echo json_encode($outArray);  
?>

this is HTML file to receive & print json data.

src=”http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js&#8221;>

//$(‘document’).ready(function() { 

    function Preload() {
    $.getJSON("http://localhost/conn_mysql.php", function(jsonData){  
    $.each(jsonData, function(i,j)
    { alert(j.options);});
    });} 

// });
    </script></head>

    <body onLoad="Preload()">
    </body>

</html> >
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1 Answer

  1. Editorial Team

    Your PHP needs to actually put all the rows together:

    $query = "SELECT * FROM user_spec"; 
$result=mysql_query($query);    
$outArray = array();
if ($result) {
  while ($row = mysql_fetch_assoc($result)) $outArray[] = $row;
}
echo json_encode($outArray);

    Your Javascript needs to look at each of the rows.. 

    $.getJSON("/whatever.php", function(jsonData) { 
   for (var x = 0; x < jsonData.length; x++) {
      alert(jsonData[x].options);
   }
});
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