Question

This is pretty strange (admitedly, this is my first attempt with python / sqlite), but I can seem to get all of the rows if I do a fetchAll(), but other than that – no matter what I try, always ends up in the db only returning the first row – the second iteration stops because a null is returned. Wondering if there is something wrong with how I am coding this up in python? The db seems ok..

con = sqlite3.connect('backup.db')
con.row_factory = sqlite3.Row
cur = con.cursor()
cur.execute('select * from tb1;')

for row in cur:
    try:
#       row = dataCur.fetchone()
        #if row == None: break
        print type(row)

        print ' Starting on: %i' % row[0]

        cleaner = Cleaner(scripts=True, remove_tags=['img'], embedded=True)
        try:
            cleaned = cleaner.clean_html(row[2]) #data stored in second col
            cur.execute('update tb1 set data = ? where id = ?;', (cleaned, row[0]))
        except AttributeError:
            print 'Attribute error'

        print ' Ended on: %i' % row[0]

    except IOError:
        print 'IOexception'

Answer 1

You are reusing the same cursor to execute two different queries. Try using two different cursors and see if that solves your problem.