Question

This is probably a really silly question but, given the example code at the bottom, how would I get a single list that retain the tuples?

(I’ve looked at itertools but it flattens everything.)

What I currently get is:

(‘id’, 20, ‘integer’)
(‘companyname’, 50, ‘text’)
[(‘focus’, 30, ‘text’), (‘fiesta’, 30, ‘text’), (‘mondeo’, 30, ‘text’), (‘puma’, 30, ‘text’)]
(‘contact’, 50, ‘text’)
(’email’, 50, ‘text’)

Instead, I need a single level list:

(‘id’, 20, ‘integer’)
(‘companyname’, 50, ‘text’)
(‘focus’, 30, ‘text’)
(‘fiesta’, 30, ‘text’)
(‘mondeo’, 30, ‘text’)
(‘puma’, 30, ‘text’)
(‘contact’, 50, ‘text’)
(’email’, 50, ‘text’)

Code:

def getproducts():
    temp_list = []

    product_list = ['focus', 'fiesta', 'mondeo', 'puma']
    # usually this would come from a db

    for p in product_list:
        temp_list.append((p, 30, 'text'))
    return temp_list

def createlist():    
    column_title_list = (
       ("id", 20, "integer"),
       ("companyname", 50, "text"),
       getproducts(), 
       ("contact", 50, "text"),
       ("email", 50, "text"),
    ) 
    return column_title_list

for item in createlist():
    print item

Answer 1

Can you make it into

[[("id",20,"integer")],
 [("companyname",50,"text")],
 getproducts(),
 ...]

? If so, you just need to concatenate the lists.

return sum(column_title_list, [])

You could also use

return [("id",20,"integer"),("companyname",50,"text")] + getproducts() + ...