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Home/ Questions/Q 631829
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:00:36+00:00 2026-05-13T20:00:36+00:00

This is probably a very basic question, but I’m really new to generics in

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This is probably a very basic question, but I’m really new to generics in Java and I’m having a hard time altering my thought process from the way things are done in C#, so bear with me.

I’m trying to build a generic repository in Java. I’ve created an IRepository interface that looks like this:

public interface IRepository<T extends IEntity>

And a Repository class that looks like this:

public class Repository<T extends IEntity> implements IRepository<T>

Now, from within the constructor of my Repository class, I’d like to be able to “divine” the exact type of T. For example, if I instantiated a repository like this:

IRepository<MyClass> repo = new Repository<MyClass>();

I’d like to know that T is actually MyClass. This is trivial in C#, but obviously generics are a totally different beast in Java and I can’t seem to find anything that would help me do this.

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:00:36+00:00Added an answer on May 13, 2026 at 8:00 pm

    Java uses type erasure, so the specific information is lost at runtime – you only know that this type is generic, not what’s the specific argument you’ve supplied at compile time.

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