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Home/ Questions/Q 5997821
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:19:06+00:00 2026-05-23T00:19:06+00:00

this is probably an essentially trivial thing, but it somewhat escapes me, thus far..

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this is probably an essentially trivial thing, but it somewhat escapes me, thus far..

char * a3[2];
a3[0] = "abc";
a3[1] = "def";
char ** p;
p = a3;

this works:

printf("%p - \"%s\"\n", p, *(++p));

this does not:

printf("%p - \"%s\"\n", a3, *(++a3));

the error i’m getting at compilation is:

lvalue required as increment operand

what am i doing wrong, why and what is the solution for ‘a3’?

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:19:07+00:00Added an answer on May 23, 2026 at 12:19 am

    a3 is a constant pointer, you can not increment it. “p” however is a generic pointer to the start of a3 which can be incremented.

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