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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T18:42:47+00:00 2026-05-31T18:42:47+00:00

This is probably the stupidest question, but I can’t find anything about it online,

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This is probably the stupidest question, but I can’t find anything about it online, and I’m partially on the verge of falling asleep.

Anyway, I’m assuming it’s got to do something with taking the total elapsed/wall time, and subtracting both the user and system time. IE, wall time is 10 seconds, system time is 2 and user is 1, meaning wait time is 7 seconds.

I’d love to get a sure-fire answer instead of using/guessing with this one that’s based on my gut.

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  1. Editorial Team
    Editorial Team
    2026-05-31T18:42:48+00:00Added an answer on May 31, 2026 at 6:42 pm

    The formula appears to be exactly as you surmised, with the caveat raised above.

    Since /usr/bin/time measures its user and system process time in CPU-seconds (according to the documentation), you’ll need to take the number of CPUs able to execute the code into account. For most simple, single-threaded applications, using one CPU as an estimate is reasonable.* In these cases, you can tolerably use CPU time as a substitute for wall clock time.

    For others, it depends on the maximum CPU saturation that program is expected to achieve, and that’s outside the scope of what time can tell you.


     * Certain processor-level idiosyncrasies with enhanced parallelism and speculative branch execution make this technically inaccurate, but it’s otherwise a reasonable estimate.

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