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Home/ Questions/Q 6210113
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:06:12+00:00 2026-05-24T06:06:12+00:00

This is purely a theoretical question, I know that if someone declares a method

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This is purely a theoretical question, I know that if someone declares a method private, you probably shouldn’t call it. I managed to call private virtual methods and change private members for instances, but I can’t figure out how to call a private non-virtual method (without using __asm). Is there a way to get the pointer to the method? Are there any other ways to do it?

EDIT: I don’t want to change the class definition! I just want a hack/workaround. 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T06:06:14+00:00Added an answer on May 24, 2026 at 6:06 am

    #include the header file, but:

    #define private public
    #define class struct
    

    Clearly you’ll need to get around various inclusion guards etc and do this in an isolated compilation unit.

    EDIT:
    Still hackish, but less so:

    #include <iostream>
    
    #define private friend class Hack; private
    
    class Foo
    {
    public:
        Foo(int v) : test_(v) {}
    private:
        void bar();
        int test_;
    };
    #undef private
    void Foo::bar() { std::cout << "hello: " << test_ << std::endl; }
    
    class Hack
    {
    public:
        static void bar(Foo& f) {
            f.bar();
        }
    };
    
    int _tmain(int argc, _TCHAR* argv[])
    {
        Foo f(42);
        Hack::bar(f);
        system("pause");
        return 0;
    }
    
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