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Editorial Team
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Asked: 2026-05-31T17:16:45+00:00

This is quite complicated but i would like to be able to refresh a

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This is quite complicated but i would like to be able to refresh a larger list once at item has been taken out of a mini list within the bigger list.

listA = ['1','2','3','4','5','6','6','8','9','5','3','7']

i used the code below to split it into lists of threes

split = [listA[i:(i+3)] for i in range(0, len(listA) - 1, 3)]

print(split)

# [['1','2','3'],['4','5','6'],['6','8','9'],['5','3','7']]

split = [['1','2','3'],['4','5','6'],['6','8','9'],['5','3','7']]

if i deleted #3 from the first list, split will now be

del split[0][-1]
split = [['1','2'],['4','5','6'],['6','8','9'],['5','3','7']]

after #3 has been deleted, i would like to be able to refresh the list so that it looks like;

split = [['1','2','4'],['5','6','6'],['8','9','5'],['3','7']]

thanks in advance

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1 Answer

  1. Editorial Team

    Not sure how big this list is getting, but you would need to flatten it and recalculate it:

    >>> listA = ['1','2','3','4','5','6','6','8','9','5','3','7']
>>> split = [listA[i:(i+3)] for i in range(0, len(listA) - 1, 3)]
>>> split
[['1', '2', '3'], ['4', '5', '6'], ['6', '8', '9'], ['5', '3', '7']]
>>> del split[0][-1]
>>> split
[['1', '2'], ['4', '5', '6'], ['6', '8', '9'], ['5', '3', '7']]
>>> listA = sum(split, []) # <- flatten split list back to 1 level
>>> listA
['1', '2', '4', '5', '6', '6', '8', '9', '5', '3', '7']
>>> split = [listA[i:(i+3)] for i in range(0, len(listA) - 1, 3)]
>>> split
[['1', '2', '4'], ['5', '6', '6'], ['8', '9', '5'], ['3', '7']]
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