Question

This is quite likely something simple that I have an issue with, but I do not have another machine to figure out if it’s my laptop’s python version right now.

When I run my program, I recieve the following error: “Type Error: function open() requires no arguments (2 given)”

The code snippet in question:

    import tkinter as tk
    from tkinter import filedialog as fdg

    def update_queue():
            conf_file = open("config.txt", "a")
            fd = fdg.LoadFileDialog(master)
            file = fd.go(pattern="*.jpg")
            conf_file.write(file)
            conf_file.close()

I’m not yet too good with Python, and would appreciate any pointers (“Your code looks twistier than last night’s burnt spaghetti” counts as well) as to why the open() function fails.

Also of note, if I call open outside of a defined function, it opens the file, and can complete all actions done on it, but if I close the file, I cannot re open the file from within a function. I attempted to use the os file functions, but recieved the error “LoadFileDialog does not work with buffer-defined file functions.” Understandable.

If I use conf_file.flush(), assuming I opened it outside of a function, will it flush whatever I write/append, so that I can read from the file again later?

EDIT: What I mean, is, will this work all the time, or would this be considered a hack?

Answer 1

is that the whole code? make sure you did not import another open function somewhere. or redefined it.