Question

This is really only easy to explain with an example, so to remove the intersection of a list from within a dict I usually do something like this:

a = {1:'', 2:'', 3:'', 4:''} exclusion = [3, 4, 5]  # have to build up a new list or the iteration breaks toRemove = [] for var in a.iterkeys():     if var in exclusion:         toRemove.append(var)  for var in toRemove:     del a[var] 

This might seem like an unusual example, but it’s surprising the number of times I’ve had to do something like this. Doing this with sets would be much nicer, but I clearly want to retain the ‘values’ for the dict.

This method is annoying because it requires two loops and an extra array. Is there a cleaner and more efficient way of doing this.

Answer 1

Consider dict.pop:

for key in exclusion:      a.pop(key, None) 

The None keeps pop from raising an exception when key isn’t a key.