Question

This is so simple but I cannot get it to work. I want to do a simple if else statement in ssh bash script. here’s my code below:

#!/bin/sh

echo -n "enter what type of logs. (ie. cpanel, apache) "
read type
if [$type == cpanel]
then
LOGTYPES ="error, access"
else
LOGTYPES ="error, access, suphp, suexec"
fi

echo -n "enter which log to tail (ie. $LOGTYPES) "
read logs
echo -n "enter last number of lines to view. (ie. 10, 5000 etc) "
read lines

tail -$lines /usr/local/$type\/logs/$logs\_log

I’ve tried everything and I keep getting this error:

[~]# /apachetail
enter what type of logs. (ie. cpanel, apache) cpanel
/apachetail: line 5: [cpanel: command not found
/apachetail: line 9: LOGTYPES: command not found
enter which log to tail (ie. )

I’ve tried the following methods, none work:

    if [$type -eq cpanel]
    if [$type -eq cpanel];
    if [$type == cpanel];
    if [$type = cpanel]
    if [$type = cpanel];
    if ["$type" = cpanel]
    if ["$type" = cpanel];
    if ["$type" == cpanel]
    if ["$type" == cpanel];
    if ["$type" -eq cpanel];
    if ["$type" -eq cpanel]

Answer 1

Change

if [$type == cpanel]

to

if [ "$type" = "cpanel" ]

and

   LOGTYPES ="error, access"

to

   LOGTYPES="error, access"

Any assignment has to be without spaces around the = (assignment operator).