Question

This is something similar to this question about
How to remove a full stop from the end of data

But in this case the data field can be like this

MyVal

 abcd.          ->>expected   abcd
 abcd..                       abcd
 abcd .                       abcd 
 abcd ..                      abcd
 ab.abb...                    ab.abb

etc….

I can do something like

Select case when like '%.' then substring(MyVal ,1,len(MyVal )-1)
       case when like '%..' then substring(MyVal ,1,len(MyVal )-2)

by matching every kind of pattern there going to be..
Since this is manual way, I am looking for a general way that can remove any number of full stop may occur after the value field.

Thanks

Answer 1

select substring(MyVal, 1, len(MyVal)+1-patindex('%[^.]%', reverse(MyVal)))

Update:
If you want to remove spaces as well you can use this instead.

select substring(MyVal, 1, len(MyVal)+1-patindex('%[^. ]%', reverse(MyVal)))

SE-Data