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Home/ Questions/Q 1074555
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:08:44+00:00 2026-05-16T21:08:44+00:00

This is something trivial, which I’ve forgotten. There are possibly duplicates – I searched

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This is something trivial, which I’ve forgotten.
There are possibly duplicates – I searched a little, found similar, but couldn’t find as concise.

   String.prototype.test = function(){this.bar = this.length + 2;}

   var str = "foo";
   str.test();

   console.log(str);                         // foo
   console.log(str.bar);                     // undefined

Pretty sure it has to do with this being trapped in the closure.

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:08:46+00:00Added an answer on May 16, 2026 at 9:08 pm

    Has to do with the way you’re creating your string in this case. Try:

    var str = new String("Foo");
    

    and you’ll find it magically working. :-]

    See an example at:
    http://jsbin.com/odozo3/edit

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