Question

This is supposed to decrypt a file. I’m trying to figure out the algorithm but am having a bit of an issue understanding what is going on. Any hints? Thanks!

      localStringBuilder1 = new StringBuilder("");
      localStringBuilder2 = new StringBuilder("");
      Matcher localMatcher = Pattern.compile("[a-zA-z_\\-]+\\.html").matcher(paramString); //paramString is the encrypted file
      localMatcher.find();
      String str2 = localMatcher.group();
for (Integer localInteger1 = Integer.valueOf(0); localInteger1
            .intValue() < str2.length(); localInteger1 = Integer
            .valueOf(1 + localInteger1.intValue())) {
        localStringBuilder2.append(1 + Math.round(str2
                .codePointAt(localInteger1.intValue()) % 3));
        if (localInteger1.intValue() < "fdjkhireuhsdthuirdfg".length())
            localStringBuilder2.append(1 + Math
                    .round("fdjkhireuhsdthuirdfg".codePointAt(localInteger1
                            .intValue()) % 3));
    }

Update: Simplified Loop

for (int i = 0; i < str2.length(); i++) {
        localStringBuilder2.append(1 + Math.round(str2
                .codePointAt(i) % 3));
        if (i < "fdjkhireuhsdthuirdfg".length())
            localStringBuilder2.append(1 + Math
                    .round("fdjkhireuhsdthuirdfg".codePointAt(i) % 3));
    }

And you can find complete source code over here

EDIT
Big thanks to Vandey who solved the string produced: “21321223331121”

This however doesn’t get the full answer.
The next part is (beats the hell out of me):

label249: if (localInteger2.intValue() < i);
    try
    {
      localStringBuilder1.append((char)(Integer.parseInt(str1.substring(0 + localInteger2.intValue(), 2 + localInteger2.intValue()), 16) - Integer.parseInt(localStringBuilder2.substring(localInteger2.intValue() / 2 % localStringBuilder2.length(), 1 + localInteger2.intValue() / 2 % localStringBuilder2.length()))));
      label327: localInteger2 = Integer.valueOf(2 + localInteger2.intValue());
      break label249;
      str3 = localStringBuilder1.toString();
    }
    catch (StringIndexOutOfBoundsException localStringIndexOutOfBoundsException)
    {
      break label327;
    }

Answer 1

str2 is hardcoded here, work for it , otherwise it shoould be pretty close to it. Anyone, feel free to edit it to the right direction. The last printline was added just to see what it prints .
And sorry for misleading variable name.

    String str2 = "abcdefg";
    String toCompare = "fdjkhireuhsdthuirdf(g"; //looks like this changed when  you updated your question
    StringBuilder sb = new StringBuilder();

    for (int i = 0; i < str2.length(); i++) {
        char ch = str2.charAt(i);
        int charInt1 = ch % 3;

        sb.append(1 + Math.round(charInt1));

        if (i < toCompare.length()) {
            char ch2 = toCompare.charAt(i);
            int charInt2 = ch2 % 3;
            sb.append(1 + Math.round(charInt2));
        }
    }
    System.out.println(sb.toString()); // printed 21321223331121