Question

This is the code. editor.php is the link. photo_id is the the information i want to pass over. $photo[‘picture’] is the photo.

     print ('<a href="editor.php?photo_id='.$photo['id'].'"><img src='{$photo['picture']}'.'</a>'./>');

Answer 1

Just use session_start(); and put you link in a $_SESSION['last_link']; and use the same function on the next page and access the value you have put in $_SESSION['last_link'] to get information about the photo and display it.

PHP Sessions

Or, if you used that kind of link, in the editor.php you can use $_GET['photo_id'] to get the id of your photo, after the user have clicked on the image to follow the link.

Edit 1:
You could try putting the right concatenation:

try this:
echo '<a href="editor.php?photo_id='.$photo['id'].'"><img src='.$photo['picture'].' /></a>';