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Home/ Questions/Q 8163539
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T19:05:05+00:00 2026-06-06T19:05:05+00:00

This is the code I used : class ResponseCodeCheck { public static void main

  • 0

This is the code I used :

class ResponseCodeCheck 
{

public static void main (String args[]) throws Exception
{

    URL url = new URL("http://www.amazon.co.jp/gp/seller/sell-your-stuff.html");
    HttpURLConnection connection = (HttpURLConnection)url.openConnection();
    connection.setRequestMethod("GET");
    connection.connect();

    int code = connection.getResponseCode();
    System.out.println("Response code of the object is "+code);
    if (code==200)
    {
        System.out.println("OK");
    }
}
}

And it gave 404 for the URL while that URL is working fine.
Any reason why ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T19:05:07+00:00Added an answer on June 6, 2026 at 7:05 pm

    CURL is saying:

    curl -v http://www.amazon.co.jp/gp/seller/sell-your-stuff.html
    * About to connect() to www.amazon.co.jp port 80 (#0)
    *   Trying 176.32.120.128... connected
    > GET /gp/seller/sell-your-stuff.html HTTP/1.1
    > User-Agent: curl/7.23.1 (x86_64-pc-win32) libcurl/7.23.1 OpenSSL/0.9.8r zlib/1.2.5
    > Host: www.amazon.co.jp
    > Accept: */*
    >
    < HTTP/1.1 301 MovedPermanently
    

    Please note HTTP/1.1 301 MovedPermanently. Are you sure you have received 404 and not 301? This is usual web practice, 301 header means that content was placed in some other location and user (browser) should navigate to it.

    Also please make sure that HttpURLConnection allows redirection.

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