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Home/ Questions/Q 225441
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:24:50+00:00 2026-05-11T19:24:50+00:00

This is the code I’m currently using. It uses the BouncyCastle Provider. static {

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This is the code I’m currently using. It uses the BouncyCastle Provider.

static
{
   Security.addProvider(new BouncyCastleProvider());
}

protected String encrypt(byte[] keyData, byte[] data) throws Exception {
   X509EncodedKeySpec keyspec = new X509EncodedKeySpec(keyData);
   KeyFactory kf = KeyFactory.getInstance("RSA", "BC");
   PublicKey pk = kf.generatePublic(keyspec);
   Cipher rsa =  Cipher.getInstance("RSA/None/OAEPWithSHA1AndMGF1Padding", "BC");
   rsa.init(Cipher.ENCRYPT_MODE, pk);
   byte[] output = rsa.doFinal(data);
   String result = base64EncodeBytes(output);
   return result;
}

I’m currently getting a

 java.lang.ArrayIndexOutOfBoundsException: too much data for RSA block
    at org.bouncycastle.jce.provider.JCERSACipher.engineDoFinal(Unknown Source)
    at javax.crypto.Cipher.doFinal(DashoA13*..)
    at Encryption.encrypt(RSAToken.java:60)
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  1. Editorial Team
    Editorial Team
    2026-05-11T19:24:50+00:00Added an answer on May 11, 2026 at 7:24 pm

    Using RSA to encrypt a lot of data is not a good practice.

    The approach taken by cryptographic protocols is to generate a symmetric key, use it to encrypt the data, then encrypt that symmetric key with RSA.

    This is how PGP and S/MIME work. It also makes it easy to allow multiple readers to decrypt the data—by encrypting the symmetric key for each intended recipient, rather than encrypting the entire data for each.

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