Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 824603
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T03:07:23+00:00 2026-05-15T03:07:23+00:00

This is the code I’m using to update an SQL database: Public Sub main()

  • 0

This is the code I’m using to update an SQL database:

Public Sub main()

    Dim cnn As ADODB.Connection
    Dim rst As ADODB.Recordset

    Set cnn = New ADODB.Connection
    Set rst = New ADODB.Recordset

    cnn.Open "ConnectionName"
    rst.ActiveConnection = cnn
    rst.CursorLocation = adUseServer

    rst.Source = "Update Table ..."
    rst.Open

    Set rst = Nothing
    Set cnn = Nothing
End Sub

What I want to know is if and how I should deal with the rst object after opening it. Do I close it? When I try doing rst.Close, I get the error: “Operation is not allowed when the object is closed”. The code works fine without rst.Close, I’m wondering if there are any dangers to not closing the object.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T03:07:23+00:00Added an answer on May 15, 2026 at 3:07 am

    An UPDATE operation does not return a resultset. Therefore, if executed with a Recordset object, it results in an empty and closed recordset. It cannot be closed anyway because it has never been opened.

    A rule of thumb is:

    if rst.State <> adStateClosed then rst.Close
    

    But, because you are executing a command that’s not going to return data anyway, the preferred way is:

    dim cm as ADODB.Command
    set cm = new adodb.command
    set cm.activeconnection = cnn
    cm.commandtype = adCmdText
    cm.commandtext = "UPDATE ..."
    
    cm.execute ,, adExecuteNoRecords
    

    Or, if your SQL is a fixed string that doesn’t have parameters,

    cnn.execute "UPDATE ...",, adExecuteNoRecords
    

    Also, please change rst.ActiveConnection = cnn to Set rst.ActiveConnection = cnn.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 532k
  • Answers 532k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Yes, it is possible to integrate the Windows Scripting into… May 17, 2026 at 12:15 am
  • Editorial Team
    Editorial Team added an answer Timeouts are not provided by the @Async annotation, since the… May 17, 2026 at 12:15 am
  • Editorial Team
    Editorial Team added an answer No, it is not the same. Differences are: User account… May 17, 2026 at 12:15 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

This code compiles on msvc/g++: class A{ protected: int i; class B{ public: A*
This code is works fine when you type 22 and 56 for example, it
This code doesn't work: URL url = new URL( xmlPath ); InputSource input =
This code compiles and works as expected (it throws at runtime, but never mind):
This code doesn't work: var number = $(this).find('.number').text(); var current = 600; if (current
This code and problem must be familiar, but I have not found anything. Any
This code $html->link( &raquo;, '/events/view/'.$event['Event']['id']), array('escape'=>false,'class'=>'more') ) Outputs <a href=/events/view/4> &amp;raquo;</a> instead of >>
this code allows you to unzip file and create a folder in documents lets
This code works fine and produces checkbuttons in a long long list. def createbutton(self,name):
This code is for Microchip's PIC32MX microprocessor. Their compiler is essentially GCC 3.4. I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.