Question

This is the code:

#include <stdio.h>
#include <stdlib.h>

void acceptMaze(char maze[ROW][COLOUMN], int nrows, int ncols)
{
    int i,j;
    for (i = 0; i < nrows; i++)
    {
        fprintf(stdout,"I = %d",i);
        for (j = 0; j < ncols; j++) 
        {
            fprintf(stdout,"J = %d",j);
            scanf("%c",&maze[i][j]);
        }
    }
}

wel while entering data it saysi =0 j=0j=1 .So you see the j=0 doesn’t remains.I am using a linux system .Can anyone fix this.

Answer 1

Your problem stems from the fact that the %c conversion specifier doesn’t skip whitespace. If there’s a newline stuck in the input stream from a previous input operation, the scanf call will read that and assign it to maze[i][j].

Here’s one workaround:

#include <ctype.h>
...
for (i = 0; i < nrows; i++)
{
  for (j = 0; i < nrows; j++)
  {
    int c;
    do c = getchar(); while (isspace(c));
    maze[i][j] = c;
  }
}

The line do c = getchar(); while (isspace(c)) will read input characters until you hit a non-whitespace character.

EDIT

Ugh, I just realized one ugly flaw of this scheme; if you want to a assign a whitespace character like a blank to your maze, this won’t work as written. Of course, you can just add to the condition expression:

do c = getchar(); while (isspace(c) && c != ' ');