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Editorial Team
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Asked: 2026-05-21T14:03:50+00:00

This is the code where I am constantly getting an error. The same include

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This is the code where I am constantly getting an error. The same include file works on the other pages, I am only getting problem on this page. Here is the error

Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in /var/www/html/spywgc/adm/ctshell/getproduct/getproduct.php on line 18

And here is the actual code : 

<?php require_once('../../../Connections/spyware_adm.php'); ?>
<?php require_once('../../../includes/lib_gen.php'); ?>

<?php
//function for returing status of website
function Visit($url)
{
    echo $url;
    mysql_select_db($database_spyware, $spyware) || die(mysql_error());
    $select_url= "select product_id from sp_url where url like '%{$url}%'";
    echo $select_url;
    $run_url= mysql_query($select_url, $spyware);
    $result_descr = mysql_fetch_assoc($run_url);
    echo $result_descr;
    return $result_descr;

}
?>
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1 Answer

  1. Editorial Team

    mysql_select_db() expects the second parameter to be a resource identifier = your connection. The problem is, that you are running this as a function, inside which your connection is not established. You have to start your function with something like this:

    function Visit($url)
{
    $spyware = mysql_connect(); // set this to connect properly
    echo $url;
    mysql_select_db($database_spyware, $spyware) || die(mysql_error());
    // the rest of your function goes on ...
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