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Home/ Questions/Q 546263
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:50:54+00:00 2026-05-13T10:50:54+00:00

This is the error that I am getting while using mysql_num_rows() function Error: Warning:

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This is the error that I am getting while using mysql_num_rows() function

Error: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource

Here is my source code:

$title = "SELECT * FROM item WHERE item.title LIKE % " .implode("% OR item.title LIKE % ", $data);

$title_result = mysql_query($title, $this->dbh);

echo mysql_num_rows($title_result);

What I am doing is creating a search for a website. Currently I am doing 4 Select statements and then I would like to total everything found in my database from all 4 of those sql statements. If I am thinking correctly the mysql_num_rows() returns the number of rows that was found from a Select statement. So in theory I was thinking that I could add them together to get my total found in a search, am I correct in this thinking if not how could I add 4 different sql select statements together?

Also my test search is in the database.

Thanks in advance for the help.

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:50:55+00:00Added an answer on May 13, 2026 at 10:50 am

    Your MySQL statement did not execute correctly. This is just a hunch, but try again after replacing your $title with the following:

    $title = 'SELECT * FROM item WHERE item.title LIKE "%'.implode('%" OR item.title LIKE "%', $data).'%"';
    

    Then later, execute it as follows:

    $result = mysql_query ($title, $this->dbh) or die (mysql_error($this->dbh));
    

    Note: this is assuming you trust $data. If it comes from external sources (such as user-specified search), you really ought to sanitise via mysql_real_escape_string or prepared statements

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