Question

This is the first table created on my own that I am trying to insert data.

Question: in my controller, I am not sure how to link the model with the actual database table to perform the INSERT.

Also in the line uc.userId = userId; I am getting the following error:

Invalid initializer member declarato

I created a model for this table:

public class RegisterModel
{
    public bool isCertified { get; set; }
    public int certType { get; set; }
    public string identifier { get; set; }
}

View:

<tr>
   <td style="font-size:10px;">Habilitar Login com Cert. Digital:</td>
   <td>@Html.CheckBoxFor(m => m.isCertified)</td>
</tr>                                      
<div id="certDigitalBlock">
<tr>
    <td class="smallField">Tipo do Certificado:</td>
    <td>@Html.DropDownListFor(m => m.certType, new SelectList(ViewBag.certType, "id","type"))</td>
</tr>
<tr>
    <td>Identificação:</td>
    <td>@Html.TextBoxFor(m => m.identifier, new { @class = "validate[required]" })      @Html.ValidationMessage("awnserVal", "*")</td>
</tr> 
</table>

Controller

using (tgpwebgedEntities context = new tgpwebgedEntities())
{
   var userID = from u in context.aspnet_Users where u.UserName == model.UserName select u.UserId;

   if (checkIsCertified == true)
   {
      UsersCertified uc = new UsersCertified {
                            uc.userId = userId;
                            uc.certTypeId = model.certType;
                            uc.keyNumber = model.identifier;
                        }

      context.SaveChanges()
   }
}

Thanks

Answer 1

UsersCertified uc = new UsersCertified {
                            uc.userId = userId;
                            uc.certTypeId = model.certType;
                            uc.keyNumber = model.identifier;
                        }

Shouldn’t be written under brackets? if you are using a constructor.

UsersCertified uc = new UsersCertified (
                            uc.userId = userId;
                            uc.certTypeId = model.certType;
                            uc.keyNumber = model.identifier;
                        )

Add this code:

context.UsersCertified .InsertOnSubmit(uc);
                context.SubmitChanges();