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Home/ Questions/Q 8115823
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T03:35:23+00:00 2026-06-06T03:35:23+00:00

This is the html I have: <div id=social> <a href=# class=twitter><span class=text>Twitter</span></a> </div> What

  • 0

This is the html I have:

<div id="social">
    <a href="#" class="twitter"><span class="text">Twitter</span></a>
</div>

What I intend to do is initially hide the span.text and when I hover over the image in the background of the div. This is my css

#social a {
    display:inline-block;
    overflow:hidden;
    padding:4px 0 0 28px;
/* left padding is for the bg image to be visible*/
}
#social a span {
    display:none;
}
#social .twitter {
    background:url(../images/social/twitter.png) no-repeat left top;
}
#social .twitter:hover {
    background:url(../images/social/twitter_hover.png) no-repeat left top;
}

And this is my js:

$("#social a.twitter").mouseover(function(){
  $("span",this).show("slow");
}).mouseout(function(){
  $("span",this).hide("slow");
});

But what happens is when I hover over the image it keeps on showing and hiding the text.. Where am I going wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T03:35:24+00:00Added an answer on June 6, 2026 at 3:35 am

    you have a very common problem, when the span shows, the mouse its not any more over the a, so the mouseout event gets called.

    to fix this use mouseenter and mouseleave events

    $("#social a.twitter").mouseenter(function(){
      $("span",this).show("slow");
    }).mouseleave(function(){
      $("span",this).hide("slow");
    });​
    

    fiddle for you 😀

    and, in css the comments are with /* */ and not with //

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