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Editorial Team
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Asked: 2026-05-23T20:00:39+00:00

This is the problem – how do I make the following work WITHOUT using

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This is the problem – how do I make the following work WITHOUT using UNION or a second select query?

Code:

$query = "SELECT DISTINCT(t.tid), IF(last_job2 <= 2000, last_job2, last_job) AS last_job
                      FROM smf_posts p
                        LEFT JOIN smf_topics t ON (p.topic_id=t.tid)"

So that when I add in the WHERE statements it can recognize the if / as of last_job?

For instance in the WHERE below

WHERE last_job < 2000

In other words, I want this “IF(last_job2 <= 2000, last_job2, last_job) AS last_job”
to be recognized by the time it reaches “WHERE last_job < 2000”. With my current code it does not follow “IF(last_job2 <= 2000, last_job2, last_job) AS last_job”.

Thanks!

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1 Answer

  1. Editorial Team

    Just a wild guess. Do you want this?:

    SELECT DISTINCT(t.tid)
     , IF(last_job2 <= 2000, last_job2, last_job) AS last_job
FROM smf_posts p
  LEFT JOIN smf_topics t ON (p.topic_id=t.tid)
WHERE IF(last_job2 <= 2000, last_job2, last_job) < 2000

    or perhaps this:

    SELECT DISTINCT(t.tid)
     , IF(last_job2 <= 2000, last_job2, last_job) AS last_job
FROM smf_posts p
  LEFT JOIN smf_topics t
    ON (p.topic_id=t.tid)
    AND IF(last_job2 <= 2000, last_job2, last_job) < 2000
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