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Home/ Questions/Q 835069
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:46:01+00:00 2026-05-15T04:46:01+00:00

This is the query for creating index create index idx_ncl_2 on BFPRODATTRASSOCIATION (value,attributeid) include

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This is the query for creating index
create index idx_ncl_2 on BFPRODATTRASSOCIATION (value,attributeid) include (productid)

Table structure of BFPRODATTRASSOCIATION

ProdAttrAssociationId bigint no 8
ProductId             bigint no 8
AttributeId           bigint  no  8
Value                 varchar no 4096

I am getting this error:

The maximum key length is 900 bytes. The index ‘idx_ncl_2’ has maximum length of 1237 bytes.

I have to create a nonclustered index on this column. Is there any way i can create index for the column which have datatype of varchar and size is greater than 900.

Please suggest.

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:46:02+00:00Added an answer on May 15, 2026 at 4:46 am

    You can’t – as the error message already clearly states, any index entry cannot be more than 900 bytes long.

    You cannot index a varchar(4096) field – period. No way around that – it’s a hard SQL Server limit – no way to configure it, change it, make it bigger. See Books Online – Maximum Size of Index Keys for confirmation.

    You need to either limit your “value” column to less than 900 bytes, or find another way to store that data – or just not include it in the index. If you only want your “value” field in the index to have a covering index (to be able to satisfy queries from the index entry), you could move the field to be an included column in the index – those don’t fall under the 900 byte limit.

    CREATE NONCLUSTERED INDEX idx_ncl_2 
      ON BFPRODATTRASSOCIATION(attributeid) 
      INCLUDE (productid, value)
    

    That index should work.

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