Question

This is the snippet of code in Java language:

 public void name(){
int value = 9;
 int o;
if(value > 9)
 o = 5;

if(value <= 9)
o = 8;

System.out.println(o);
}

Why does compiler can’t see the second if statement considering the last option of the value?
It won’t compile.
Best regards

Answer 1

The compiler must treat value as changeable unless you say otherwise. Declaring it final fixes the problem:

public void name(){
    final int value = 9;
    int o;
    if(value > 9) o = 5;
    if(value <= 9) o = 8;
    System.out.println(o);
}