Question

This is the whole script, that for some mysterious to me reason outputs “642”

#!usr/bin/perl 
%vvv = (1,2,3,4,5,6);
$#vvv--;
%vvv = reverse %vvv;
print keys %vvv, "\n";

Also what does “keys” in the last statement do? Thanks for your time. I am just on hurry I don’t have proper time to do my research. So again I appreciate you input.

Answer 1

$#vvv– looks like a comment. What’s happening is the hash, being an even numbered element array, is just being reverse. So it goes from:

%vvv = (
    1 => 2,
    3 => 4,
    5 => 6
);

to:

%vvv = (
    6 => 5,
    4 => 3,
    2 => 1
);

So when the keys are printed, it grabs 642, or the new, current keys of the hash.