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Home/ Questions/Q 6716831
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:46:50+00:00 2026-05-26T08:46:50+00:00

This is very strange. itoa(); seems to create an infinite loop. for(int i =

  • 0

This is very strange. itoa(); seems to create an infinite loop.

for(int i = 0; i < 10; i++)
{
        char buffer[1];
        itoa(i, buffer, 10);
        std::cout << buffer;
}

Why on earth does it do that? I’ve tried using different variables than i, numerical values without variables (i.e. itoa(1, buffer, 10);), it still keeps ending up in an infinite loop.
I’ve tried to google without much success, I found an old mail about it here.
I am using Windows XP 32 bit and Code::Blocks (with GCC) as a compiler.

Does anyone know what’s wrong? Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:46:50+00:00Added an answer on May 26, 2026 at 8:46 am

    itoa null-terminates the string it produces, but you haven’t made buffer large enough to hold the terminating NUL character. Try:

    for (int i = 0; i < 10; i++)
    {
        char buffer[2];
        itoa(i, buffer, 10);
        std::cout << buffer;
    }
    
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