Question

This is what I have so far:

def get_concrete_name_of_class(klass):
"""Given a class return the concrete name of the class.

klass - The reference to the class we're interested in.
"""

# TODO: How do I check that klass is actually a class?
# even better would be determine if it's old style vs new style
# at the same time and handle things differently below.

# The str of a newstyle class is "<class 'django.forms.CharField'>"
# so we search for the single quotes, and grab everything inside it,
# giving us "django.forms.CharField"
matches = re.search(r"'(.+)'", str(klass))
if matches:
    return matches.group(1)

# Old style's classes' str is the concrete class name.
return str(klass)

So this works just fine, but it seems pretty hackish to have to do a regex search on the string of the class. Note that I cannot just do klass().__class__.__name__ (can’t deal with args, etc.).

Also, does anyone know how to accomplish the TODO (check if klass is a class and whether its oldstyle vs new style)?

Any suggestions would be greatly appreciated.

Based on the comments here’s what I ended up with:

def get_concrete_name_of_class(klass):
    """Given a class return the concrete name of the class.

    klass - The reference to the class we're interested in.

    Raises a `TypeError` if klass is not a class.
    """

    if not isinstance(klass, (type, ClassType)):
        raise TypeError('The klass argument must be a class. Got type %s; %s' % (type(klass), klass))

    return '%s.%s' % (klass.__module__, klass.__name__)

Answer 1

How about just using klass.__name__, or to get the fully qualified name, klass.__module__+'.'+klass.__name__?