Question

This is what I tried:

Math.min([1,2,3])

But only get NaN…

Answer 1

use apply:

Math.min.apply(null,[1,2,3]); //=> 1

From devguru:

Function.apply(thisArg[, argArray])
the apply method allows you to call a
function and specify what the keyword
this will refer to within the context
of that function. The thisArg argument
should be an object. Within the
context of the function being called,
this will refer to thisArg. The second
argument to the apply method is an
array. The elements of this array will
be passed as the arguments to the
function being called. The argArray
parameter can be either an array
literal or the deprecated arguments
property of a function.

In this case the first argument is of no importance (hence: null), the second is, because the array is passed as arguments to Math.min. So that’s the ‘trick’ used here.

[edit nov. 2020] This answer is rather old. Nowadays (with Es20xx) you can use the spread syntax to spread an array to arguments for Math.min.

Math.min(...[1,2,3]);