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Home/ Questions/Q 8452109
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T11:25:04+00:00 2026-06-10T11:25:04+00:00

This is what I’ve had in mind but of course it doesn’t work. @{

  • 0

This is what I’ve had in mind but of course it doesn’t work.

@{
    var textBoxData = form.find('input[name="textboxList"]').val();
 } 
<input type="button" value="Add"  title="Add"  onclick="location.href='@Url.Action("Create_Add", "Controller", new { textboxList = textBoxData })'" />

How should I pass this? Controller action name and parameter are correct. Just that I don’t know how to get the value entered in textbox…

I have trouble with saving a form within a form, so someone suggested this solution. Proxy code would be:

<firstForm>
   textboxfor Name
   dropdownfor DType

   If DTypeDDL value is "List" then
       <secondForm>
            textboxfor nameOfItem
            submitSecondForm (using that method i mentioned above)
       </secondForm>
   End If

   submitFirstForm
</firstForm>

I’ve been trying to save 2 forms for quite a while now but no luck. This is basically my last resort.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T11:25:05+00:00Added an answer on June 10, 2026 at 11:25 am

    First of all, you should go with a viewmodel oriented html file since you are using MVC (Model, View, Controller):

    Create a viewModel:

    public class ExampleViewModel
    {
        public ExampleViewModel()
        {
        }
    
        public virtual string TextBoxData { get; set; }
    }
    

    After, code your html using the viewmodel as model:

    @model Models.Views.ExampleViewModel
    @using (Html.BeginForm())
    {
    <div class="editor-row">
            <div class="editor-label">
                @Html.LabelFor(model => model.TextBoxData)
            </div>
            <div class="editor-field">
                @Html.EditorFor(model => model.TextBoxData)
            </div>
    </div>
    <input type="submit" value="submit" />
    }
    

    and your controller:

    public ActionResult Example()
    {
        ExampleViewModel model = new ExampleViewModel();
        return This.View(model);
    }
    
    [HttpPost]
    public ActionResult Example(ExampleViewModel model)
    {
        string infoEntered = model.TextBoxData;
        // Do something with infoEntered
    }
    

    Hope this will help you!

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